x^2+3.2x-0.27=0

Solution for x^2+3.2x-0.27=0 equation:

x^2+3.2x-0.27=0

a = 1; b = 3.2; c = -0.27;
Δ = b2-4ac
Δ = 3.22-4·1·(-0.27)
Δ = 11.32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.2)-\sqrt{11.32}}{2*1}=\frac{-3.2-\sqrt{11.32}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.2)+\sqrt{11.32}}{2*1}=\frac{-3.2+\sqrt{11.32}}{2}
$